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schollz/pake

Fork: 14 Star: 208 (更新于 2024-11-03 13:34:10)

license: MIT

Language: Go .

PAKE library for generating a strong secret between parties over an insecure channel

最后发布版本: v3.0.5 ( 2022-11-19 12:54:29)

GitHub网址

pake

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This library will help you allow two parties to generate a mutual secret key by using a weak key that is known to both beforehand (e.g. via some other channel of communication). This is a simple API for an implementation of password-authenticated key exchange (PAKE). This protocol is derived from Dan Boneh and Victor Shoup's cryptography book (pg 789, "PAKE2 protocol). I decided to create this library so I could use PAKE in my file-transfer utility, croc.

Install

go get -u github.com/schollz/pake/v3

Usage

Explanation of algorithm

// both parties should have a weak key
weakKey := []byte{1, 2, 3}

// initialize A
A, err := pake.InitCurve(weakKey, 0, "siec")
if err != nil {
    panic(err)
}
// initialize B
B, err := pake.InitCurve(weakKey, 1, "siec")
if err != nil {
    panic(err)
}

// send A's stuff to B
err = B.Update(A.Bytes())
if err != nil {
    panic(err)
}

// send B's stuff to A
err = A.Update(B.Bytes())
if err != nil {
    panic(err)
}

// both P and Q now have strong key generated from weak key
kA, _ := A.SessionKey()
kB, _ := B.SessionKey()
fmt.Println(bytes.Equal(kA, kB))
// Output: true

When passing P and Q back and forth, the structure is being marshalled using Bytes(), which prevents any private variables from being accessed from either party.

Each function has an error. The error become non-nil when some part of the algorithm fails verification: i.e. the points are not along the elliptic curve, or if a hash from either party is not identified. If this happens, you should abort and start a new PAKE transfer as it would have been compromised.

Hard-coded elliptic curve points

The elliptic curve points are hard-coded to prevent an application from allowing users to supply their own points (which could be backdoors by choosing points with known discrete logs). Public points can be verified via sage using hashes of croc1 and croc2:

all_curves = {}

# SIEC
K.<isqrt3> = QuadraticField(-3)
pi = 2^127 + 2^25 + 2^12 + 2^6 + (1 - isqrt3)/2
p = ZZ(pi.norm())

E = EllipticCurve(GF(p),[0,19]) # E: y^2 = x^3 + 19
G = E([5,12])

all_curves["siec"] = E


# 521r1
S = 0xD09E8800291CB85396CC6717393284AAA0DA64BA
p = 0x01FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF
a = 0x01FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFC
b = 0x0051953EB9618E1C9A1F929A21A0B68540EEA2DA725B99B315F3B8B489918EF109E156193951EC7E937B1652C0BD3BB1BF073573DF883D2C34F1EF451FD46B503F00
Gx= 0x00C6858E06B70404E9CD9E3ECB662395B4429C648139053FB521F828AF606B4D3DBAA14B5E77EFE75928FE1DC127A2FFA8DE3348B3C1856A429BF97E7E31C2E5BD66
Gy= 0x011839296A789A3BC0045C8A5FB42C7D1BD998F54449579B446817AFBD17273E662C97EE72995EF42640C550B9013FAD0761353C7086A272C24088BE94769FD16650
n = 0x01FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFA51868783BF2F966B7FCC0148F709A5D03BB5C9B8899C47AEBB6FB71E91386409

E = EllipticCurve(GF(p),[a,b])
all_curves["P-521"] = E

# P-256
p = 115792089210356248762697446949407573530086143415290314195533631308867097853951
r = 115792089210356248762697446949407573529996955224135760342422259061068512044369
s = 0xc49d360886e704936a6678e1139d26b7819f7e90
c = 0x7efba1662985be9403cb055c75d4f7e0ce8d84a9c5114abcaf3177680104fa0d
b = 0x5ac635d8aa3a93e7b3ebbd55769886bc651d06b0cc53b0f63bce3c3e27d2604b
Gx = 0x6b17d1f2e12c4247f8bce6e563a440f277037d812deb33a0f4a13945d898c296
Gy = 0x4fe342e2fe1a7f9b8ee7eb4a7c0f9e162bce33576b315ececbb6406837bf51f5 

E = EllipticCurve(GF(p),[-3,b])
G = E([Gx,Gy])
all_curves["P-256"] = E

# P-384
p = 39402006196394479212279040100143613805079739270465446667948293404245721771496870329047266088258938001861606973112319
r = 39402006196394479212279040100143613805079739270465446667946905279627659399113263569398956308152294913554433653942643
s = 0xa335926aa319a27a1d00896a6773a4827acdac73
c = 0x79d1e655f868f02fff48dcdee14151ddb80643c1406d0ca10dfe6fc52009540a495e8042ea5f744f6e184667cc722483
b = 0xb3312fa7e23ee7e4988e056be3f82d19181d9c6efe8141120314088f5013875ac656398d8a2ed19d2a85c8edd3ec2aef
Gx = 0xaa87ca22be8b05378eb1c71ef320ad746e1d3b628ba79b9859f741e082542a385502f25dbf55296c3a545e3872760ab7
Gy = 0x3617de4a96262c6f5d9e98bf9292dc29f8f41dbd289a147ce9da3113b5f0b8c00a60b1ce1d7e819d7a431d7c90ea0e5f
E = EllipticCurve(GF(p),[-3,b])
G = E([Gx,Gy])
all_curves["P-384"] = E


import hashlib

def find_point(E,seed=b""):
    X = int.from_bytes(hashlib.sha1(seed).digest(),"little")
    while True:
        try:
            return E.lift_x(E.base_field()(X)).xy()
        except:
            X += 1

    
for key,E in all_curves.items():
    print(f"key = {key}, P = {find_point(E,seed=b'croc2')}")
    print(f"key = {key}, P = {find_point(E,seed=b'croc1')}")

which returns

key = siec, P = (793136080485469241208656611513609866400481671853, 18458907634222644275952014841865282643645472623913459400556233196838128612339)
key = siec, P = (1086685267857089638167386722555472967068468061489, 19593504966619549205903364028255899745298716108914514072669075231742699650911)
key = P-521, P = (793136080485469241208656611513609866400481671852, 4032821203812196944795502391345776760852202059010382256134592838722123385325802540879231526503456158741518531456199762365161310489884151533417829496019094620)
key = P-521, P = (1086685267857089638167386722555472967068468061489, 5010916268086655347194655708160715195931018676225831839835602465999566066450501167246678404591906342753230577187831311039273858772817427392089150297708931207)
key = P-256, P = (793136080485469241208656611513609866400481671852, 59748757929350367369315811184980635230185250460108398961713395032485227207304)
key = P-256, P = (1086685267857089638167386722555472967068468061489, 9157340230202296554417312816309453883742349874205386245733062928888341584123)
key = P-384, P = (793136080485469241208656611513609866400481671852, 7854890799382392388170852325516804266858248936799429260403044177981810983054351714387874260245230531084533936948596)
key = P-384, P = (1086685267857089638167386722555472967068468061489, 21898206562669911998235297167979083576432197282633635629145270958059347586763418294901448537278960988843108277491616)

which are the points used in the code.

Contributing

Pull requests are welcome. Feel free to...

  • Revise documentation
  • Add new features
  • Fix bugs
  • Suggest improvements

Thanks

Thanks @tscholl2 for lots of implementation help, fixes, and developing the novel "siec" curve.

License

MIT

最近版本更新:(数据更新于 2024-09-13 19:16:54)

2022-11-19 12:54:29 v3.0.5

2022-02-23 23:26:00 v3.0.4

2022-02-04 00:36:59 v3.0.3

2021-05-08 01:15:11 v3.0.2

2021-04-18 05:30:30 v3.0.1

2021-04-18 05:29:19 v3.0.0

2020-05-07 01:47:24 v2.0.3

2019-11-13 07:29:32 v2.0.2

2018-09-07 22:30:42 v1.0.2

2018-07-01 21:40:21 v1.0.0

主题(topics):

cryptography, golang, library, pake

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